# Binary to Octal Conversion

“** Binary to Octal Conversion**” is one of the classic programming problem for beginners. Here, we are given a Binary Number, entered by user and our task is to write a program to convert the given binary number to its equivalent octal number.

*Example (**Binary** to Octal Conversion):*

Binary = 100011011 Octal = 433

The steps required for Binary to Octal Conversion are as follows:

- Make sure the number of digits in binary number is divisible by 3. If not, add extra 0s in front.
- Divide the binary number into pairs of 3-digit binary number.
- Convert each 3-digit binary number pair to its decimal form.
- Combine all the decimal numbers and store into ‘Octal’.
- Print the result.

**C++ Program for Binary to Octal Conversion is as follows:**

/* C++ Program for Binary to Octal Conversion Number*/ #include<bits/stdc++.h> using namespace std; int main() { /* Scan the Binary Number */ string Binary; cout<<"Enter the Binary Number: "; cin>>Binary; /* Converting Binary to Octal*/ /* Make sure the number of digits in 'Binary' Number is divisible by 3. If not, add required 0s in front*/ while(Binary.length() % 3 != 0) { Binary.insert(0,"0"); } /* Converting each digit of Binary number into 3-digit binary number pair and convert each pair to its corresponding decimal */ string Octal = ""; for(int i = 0; i < Binary.length(); i=i+3) { string temp; temp = temp + Binary[i]; temp = temp + Binary[i+1]; temp = temp + Binary[i+2]; if(temp == "000") Octal += '0'; else if(temp == "001") Octal += '1'; else if(temp == "010") Octal += '2'; else if(temp == "011") Octal += '3'; else if(temp == "100") Octal += '4'; else if(temp == "101") Octal += '5'; else if(temp == "110") Octal += '6'; else if(temp == "111") Octal += '7'; } /*Printing the result */ cout<<"The Octal of "<<Binary<<" is "<<Octal; }

Enter the Binary Number: 100011011 The Octal of 100011011 is 433OUTPUT:

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