# Print All Nodes of Binary Tree That Do not Have Siblings

Print All Nodes of Binary Tree That Do not Have Siblings” is one of foremost algorithmic problem asked in a technical interview of product-based companies. Here, we are given a binary tree and our task is to write a program to print all nodes of binary tree that don’t have siblings.

Sibling Nodes: Two Nodes are said to be sibling nodes if the parent node of both nodes is same. Any Node can have at most one sibling. Root node does not have any sibling.

We can solve the following problem both recursively and iteratively. Here, the idea is that for any node (not leaf node), check if it has only one child node or have both child nodes. If only one child node is present, then print that node and continue traversal. If both child nodes are present, then simply continue traversal.

METHOD 1: Recursive Solution

#### C++ Program to print all nodes of Binary Tree that do not have siblings is as follows:

```/* C++ Program to print all nodes of Binary Tree that do not have siblings */
#include<bits/stdc++.h>
using namespace std;

typedef struct Node
{
int data;
struct Node *left;
struct Node *right;
Node(int ele)
{
data = ele;
left = NULL;
right = NULL;
}
} Node;

/* Function to print all nodes of Binary Tree that don’t have siblings */
void printSingleSiblings(Node *root)
{
/* Bssic Case: Null Tree */
if(root == NULL)
return;

/* If only right child is present, print it and recursively traversel right subtree */
if(root -> left == NULL && root -> right != NULL)
{
cout<<root -> right -> data<<" ";
printSingleSiblings(root -> right);
}

/* If only left child is present, print it and recursively traversel left subtree */
else if(root -> left != NULL && root -> right == NULL)
{
cout<<root -> left -> data<<" ";
printSingleSiblings(root -> left);
}

/* If both childs are present, recursively traverse them */
else
{
printSingleSiblings(root -> left);
printSingleSiblings(root -> right);
}
}

int main()
{
/* Creating a Binary trees and inserting some nodes in it */
Node *root = NULL;

root = new Node(1);
root -> left = new Node(2);
root -> right = new Node(3);
root -> left -> left = new Node(4);
root -> left -> right = new Node(5);
root -> right -> left = new Node(6);
root -> right -> right = new Node (7);
root -> left -> right -> left = new Node(8);
root -> right -> left -> right = new Node(9);

/* Calling function to print all nodes of Binary Tree that do not have siblings */
cout<<"Nodes in a tree that don't have siblings are:\n";
printSingleSiblings(root);
}
```

OUTPUT:

```Nodes in a tree that don't have siblings are:
8 9```

METHOD 2: Iterative Solution

#### C++ Program to print all nodes of Binary Tree that do not have siblings is as follows:

```/* C++ Program to print all nodes of Binary Tree that do not have siblings */
#include<bits/stdc++.h>
using namespace std;

typedef struct Node
{
int data;
struct Node *left;
struct Node *right;
Node(int ele)
{
data = ele;
left = NULL;
right = NULL;
}
} Node;

/* Function to print all nodes of Binary Tree that do not have siblings */
void printSingleSiblings(Node *root)
{
/* Bssic Case: Null Tree */
if(root == NULL)
return;

queue<Node *> que;
que.push(root);

while(!que.empty())
{
Node *temp = que.front();

que.pop();

if(temp -> left == NULL && temp -> right != NULL)
{
cout<<temp -> right -> data<<" ";
que.push(temp -> right);
}
else if(temp -> left != NULL && temp -> right == NULL)
{
cout<<temp -> left -> data<<" ";
que.push(temp -> left);
}
else if(temp -> left != NULL && temp -> right != NULL)
{
que.push(temp -> left);
que.push(temp -> right);
}
}
}

int main()
{
/* Creating a Binary trees and inserting some nodes in it */
Node *root = NULL;

root = new Node(1);
root -> left = new Node(2);
root -> right = new Node(3);
root -> left -> left = new Node(4);
root -> left -> right = new Node(5);
root -> right -> left = new Node(6);
root -> right -> right = new Node (7);
root -> left -> right -> left = new Node(8);
root -> right -> left -> right = new Node(9);

/* Calling function to print all nodes of Binary Tree that do not have siblings */
cout<<"Nodes in a tree that don't have siblings are:\n";
printSingleSiblings(root);
}

```

OUTPUT:

```Nodes in a tree that don't have siblings are:
8 9```

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