# Hexadecimal to Binary Conversion

“** Hexadecimal to Binary Conversion**” is one of the classic programming problem exercise. Here, we are given a hexadecimal number, entered by user and our task is to write a program to convert the given hexadecimal number to its equivalent binary number.

*Example:*

Hexadecimal Number: 32A Binary Number: 1100101010

The steps required for hexadecimal to binary conversion are as follows:

- Scan the hexadecimal number from left to right digit by digit.
- Convert each digit of hexadecimal number into its corresponding 4-digit binary number, combine them and store it into result.
- Print the result.

**C++ Program for hexadecimal to binary conversion is as follows:**

/* C++ Program for Hexadecimal to Binary Conversion */ #include<bits/stdc++.h> using namespace std; int main() { /* Scan the hexadecimal Number */ string Hexadecimal; cout<<"Enter the Hexadecimal Number: "; cin>>Hexadecimal; /* Converting Hexadecimal to Binary*/ string Binary; /* Converting each digit of hexadecimal number to 4-digit binary number and store the combined result into 'Binary' */ for(int i = 0; i < Hexadecimal.length(); i++) { string temp; switch(Hexadecimal[i]) { case '0': temp = "0000"; break; case '1': temp = "0001"; break; case '2': temp = "0010"; break; case '3': temp = "0011"; break; case '4': temp = "0100"; break; case '5': temp = "0101"; break; case '6': temp = "0110"; break; case '7': temp = "0111"; break; case '8': temp = "1000"; break; case '9': temp = "1001"; break; case 'A': temp = "1010"; break; case 'B': temp = "1011"; break; case 'C': temp = "1100"; break; case 'D': temp = "1101"; break; case 'E': temp = "1110"; break; case 'F': temp = "1111"; } /* Combining the 4-digit binary numbers */ Binary = Binary + temp; } /* Truncating Extra 0s from beginning, if any */ while(Binary[0]=='0') { Binary.erase(Binary.begin()+0); } /*Printing the result */ cout<<"The Binary of "<<Hexadecimal<<" is "<<Binary; }

Enter the Hexadecimal Number: 32A The Binary of 32A is 1100101010OUTPUT:

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