Check if two trees are mirror tree of each other
“Check if two trees are mirror tree of each other” is a basic problem based on tree data structure. Here, we are given two binary tree and our task is to write a program to check whether given two binary trees are mirror tree of each other.
Two trees are known as mirror tree of each other if they satisfy following conditions:
- Both must be empty or non-empty tree.
- Root Node data must be same.
- Left subtree of first tree must be equal to right subtree of second tree.
- Right subtree of first tree must be equal to left subtree of second tree.
C++ Program to check if two trees are mirror tree of each other is as follows:
/* C++ Program to check if two trees are mirror tree of each other */
#include<bits/stdc++.h>
using namespace std;
typedef struct Node
{
int data;
struct Node *left;
struct Node *right;
Node(int ele)
{
data = ele;
left = NULL;
right = NULL;
}
} Node;
/* Function to check if two trees are mirror tree of each other */
bool checkMirror(Node *root1, Node *root2)
{
/* Base Case1: If both Trees are Empty */
if(root1 == NULL && root2 == NULL)
return true;
/* Base Case2: If one tree is empty and other not */
if(root1 == NULL || root2 == NULL)
return false;
/*
If Both are Non-Empty, Recursively compare data of left subtree of
first tree with right subtree of second tree and vice-versa
*/
return root1 -> data == root2 -> data &&
checkMirror(root1 -> left, root2 -> right) &&
checkMirror(root1 -> right,root2 -> left);
}
int main()
{
/* Creating a Binary trees and inserting some nodes in it */
Node *root1 = NULL;
Node *root2 = NULL;
/* Inserting some Nodes in first tree */
root1 = new Node(1);
root1 -> left = new Node(2);
root1 -> right = new Node(3);
root1 -> left -> left = new Node(4);
root1 -> left -> right = new Node(5);
root1 -> right -> left = new Node(6);
root1 -> right -> right = new Node (7);
root1 -> left -> right -> left = new Node(8);
root1 -> right -> left -> right = new Node(9);
/* Inserting some Nodes in second tree */
root2 = new Node(1);
root2 -> right = new Node(2);
root2 -> left = new Node(3);
root2 -> right -> right = new Node(4);
root2 -> right -> left = new Node(5);
root2 -> left -> right = new Node(6);
root2 -> left -> left = new Node (7);
root2 -> right -> left -> right = new Node(8);
root2 -> left -> right -> left = new Node(9);
/* Calling function to check if two trees are mirror tree of each other*/
if(checkMirror(root1,root2) == true)
{
cout<<"Both Trees are Mirror Tree of Each Other!!";
}
else
{
cout<<"Both Trees are not Mirror Tree of Each Other!!";
}
}
OUTPUT:
Both Trees are Mirror Tree of Each Other!!
Related Posts:
- Convert Binary Tree to its Mirror Tree
- Check if Binary Tree is Symmetric or Not
- Print All Root to Leaf Paths in a Binary Tree
- Introduction to Tree Data Structure
- Binary Tree Traversals
- Print All Leaf Nodes of a Binary Tree
- Count Number of Nodes in a Binary Tree
- Print Alternate Levels of Binary Tree
- Maximum Width of Binary Tree
- Level Order Tree Traversal
- Left View of Binary Tree
- Right View of Binary Tree
- Compute Height of Binary Tree
- Inorder Tree Traversal Using Stack
- Preorder Tree Trasversal Using Stack
- Postorder Tree Traversal Using Stack
- Vertical Order Tree Traversal
- Top View of Binary Tree
- Bottom View of Binary Tree
- Delete Complete Binary Tree