# Transpose of a Matrix

“** Transpose of a matrix**” is a basic problem on matrix where we interchange the row and columns with each other. Here, we are given a matrix of size N*M and our task is to find the transpose of the matrix by interchanging the row and columns.

**Example:**

N = 3, M = 2

1 | 2 |

3 | 4 |

5 | 6 |

1 | 3 | 5 |

2 | 4 | 6 |

**C++ Program to find transpose of a matrix is as follows:**

#include<bits/stdc++.h> using namespace std; int main() { int N,M; // Scan Dimensions of the matrix cout<<"Enter the dimensions of the matrix: "; cin>>N>>M; int matrix[N][M]; int transpose[M][N]; // Scan Matrix Elements cout<<"Enter the elements of first matrix:"; for(int i = 0 ; i < N ; i++) for(int j = 0 ; j < M ; j++) cin>>matrix[i][j]; // Transpose Matrix for (int i = 0; i < N; ++i) for (int j = 0; j < M; ++j) transpose[j][i] = matrix[i][j]; //Print Transposed matrix cout<<"The Transposed Matrix is:\n"; for(int i = 0 ; i < M ; i++) { for(int j = 0 ; j < N ; j++) { cout<<transpose[i][j]<<" "; } cout<<endl; } }

Enter the dimensions of the matrix: 3 2 Enter the elements of matrix: 1 2 3 4 5 6 The Transposed Matrix is: 1 3 5 2 4 6OUTPUT: